2x-3=x^2+2x+3

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Solution for 2x-3=x^2+2x+3 equation: 



2x-3=x^2+2x+3

We move all terms to the left:

2x-3-(x^2+2x+3)=0

We get rid of parentheses

-x^2+2x-2x-3-3=0

We add all the numbers together, and all the variables

-1x^2-6=0

a = -1; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-1)·(-6)
Δ = -24
Delta is less than zero, so there is no solution for the equation

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